# How do you evaluate #5e^(3x+7)=21#?

##### 1 Answer

Mar 6, 2016

#### Explanation:

Divide both sides by

#e^(3x+7)=21/5#

To undo the exponential function with a base of

#ln(e^(3x+7))=ln(21/5)#

#3x+7=ln(21/5)#

Subtract

#3x=ln(21/5)-7#

Divide both sides by

#x=(ln(21/5)-7)/3approx-1.8550#